document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1024911>Question 1024911</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Carol is three times as old as John who is ten years older than Henry. The sum of their ages is 140 years. Calculate their ages.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #640277 by </B><A HREF=/tutors/aboutme.mpl?userid=Timnewman><B>Timnewman(323)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Timnewman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Timnewman><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=640277\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let henry's age be x,<BR>\n" );
document.write( "John's age =10+x<BR>\n" );
document.write( "Carol's age=3(10+x)=30+3x<BR>\n" );
document.write( "but the sum of their ages is 140yrs,<BR>\n" );
document.write( "Then,<BR>\n" );
document.write( "x+30+3x+10+x=140<BR>\n" );
document.write( "5x+40=140<BR>\n" );
document.write( "5x=140-40<BR>\n" );
document.write( "5x=100<BR>\n" );
document.write( "x=20<BR>\n" );
document.write( "hary's age is 20yrs<BR>\n" );
document.write( "carol's age is 30+3(20)=90yrs<BR>\n" );
document.write( "John;s age=10+20=30yrs </SPAN>\n" );
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