document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1024790>Question 1024790</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Landon climbs hill@.5 rate slower than coming down. If it takes him 4hr to climb and 216 to come down what is rate coming down? 216/60= 3.6 takes Landon 18/5 hrs to come down. <BR>\n" );
document.write( "(R-.5)(4)=r(18/5)=4R-2=(18/5)r<BR>\n" );
document.write( "4r-4r-2=18/5r -4r = -2=-2/5, how did -4r-r 18/5 =-2/5?? Help!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #640273 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=640273\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Landon climbs hill@.5 rate slower than coming down. If it takes him 4hr to climb and 216 to come down what is rate coming down? 216/60= 3.6 takes Landon 18/5 hrs to come down. <BR>\n" );
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document.write( "4 hours up, and 216 hours down?<BR>\n" );
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document.write( "You can't find the rates up and down without knowing the distance. </SPAN>\n" );
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