document.write( "Question 1024820: A company determines that its daily revenue R(in dollars) for selling X items is modeled by the equation R=x(150-x). How many items must be sold for its revenue to be $4400? \n" ); document.write( "
Algebra.Com's Answer #640240 by Theo(13342) You can put this solution on YOUR website! equation becomes 4400 = x * (150 - x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get 4400 = 150x - x^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "add x^2 to both sides of the equation and subtract 150x from both sides of the equation to get x^2 - 150x + 4400 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factor this equation to get x = 40 or x = 110.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x can be equal to 40 or x can be equal to 110.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 40, the equation becomes 4400 = 40 * (150 - 40) which becomes 4400 = 4400.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 110, the equation becomes 4400 = 110 * (150 - 110) which becomes 4400 = 4400.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so the company either sells 40 items at 110 apiece, or the company sells 110 items at 40 apiece to get a revenue of 4400.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |