document.write( "Question 1024875: Hi everyone, please can you help me with a maths problem: I am a odd 3 digit number, that is equal to another number multiplied by itself. the sum of my digits is 16. what number am i.
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document.write( "Thanks!!! \n" );
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Algebra.Com's Answer #640236 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! The number that is multiplied by itself can't be a \n" ); document.write( "1-digit number. It can't be a 3-digit number, so \n" ); document.write( "it must be a 2-digit number. \n" ); document.write( "------------------------- \n" ); document.write( "Also, the units digit must be odd since \n" ); document.write( "( odd )x( odd) = odd in order to make \n" ); document.write( "------------------------- \n" ); document.write( "It can't be as large as \n" ); document.write( "I could be as large as \n" ); document.write( "It could be as small as \n" ); document.write( "------------------------- \n" ); document.write( "So, the possible numbers and their squares are: \n" ); document.write( "11 - 121 \n" ); document.write( "13 - 169 \n" ); document.write( "15 - 225 \n" ); document.write( "17 - 289 \n" ); document.write( "19 - 361 \n" ); document.write( "21 - 441 \n" ); document.write( "23 - 529 \n" ); document.write( "25 - 625 \n" ); document.write( "27 - 729 \n" ); document.write( "29 - 841 \n" ); document.write( "31 - 961 \n" ); document.write( "--------- \n" ); document.write( "The sum of the digits of \n" ); document.write( "The sum of the digits of \n" ); document.write( "The sum of the digits of \n" ); document.write( "---------- \n" ); document.write( "I think the number can be \n" ); document.write( "169, 529, or 961 \n" ); document.write( " |