document.write( "Question 1024875: Hi everyone, please can you help me with a maths problem: I am a odd 3 digit number, that is equal to another number multiplied by itself. the sum of my digits is 16. what number am i.
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Algebra.Com's Answer #640236 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The number that is multiplied by itself can't be a
\n" ); document.write( "1-digit number. It can't be a 3-digit number, so
\n" ); document.write( "it must be a 2-digit number.
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\n" ); document.write( "Also, the units digit must be odd since
\n" ); document.write( "( odd )x( odd) = odd in order to make \"+c+\" odd
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\n" ); document.write( "It can't be as large as \"+33+\", since \"+33%5E2+=+1089+\"
\n" ); document.write( "I could be as large as \"+31+\", since \"+31%5E2+=+961+\"
\n" ); document.write( "It could be as small as \"+11+\", since \"+11%5E2+=+121+\"
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\n" ); document.write( "So, the possible numbers and their squares are:
\n" ); document.write( "11 - 121
\n" ); document.write( "13 - 169
\n" ); document.write( "15 - 225
\n" ); document.write( "17 - 289
\n" ); document.write( "19 - 361
\n" ); document.write( "21 - 441
\n" ); document.write( "23 - 529
\n" ); document.write( "25 - 625
\n" ); document.write( "27 - 729
\n" ); document.write( "29 - 841
\n" ); document.write( "31 - 961
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\n" ); document.write( "The sum of the digits of \"+13%5E2+=+169+\" is \"+16+\"
\n" ); document.write( "The sum of the digits of \"+23%5E2+=+529+\" is \"+16+\"
\n" ); document.write( "The sum of the digits of \"+31%5E2+=+961+\" is \"+16+\"
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\n" ); document.write( "I think the number can be
\n" ); document.write( "169, 529, or 961
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