document.write( "Question 1024859: A jogger starts from one end of a 12-mile nature trail at 8:00 A.M. One hour later, a cyclist starts from the other end of the trail and rides toward the jogger. If the rate of the jogger is 6 mph and the rate of the cyclist is 12 mph, at what time will the two meet? \n" ); document.write( "
Algebra.Com's Answer #640220 by josgarithmetic(39617)\"\" \"About 
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document.write( "                   rate             time          distance\r\n" );
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document.write( "JOGGER              6               t+1\r\n" );
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document.write( "CYCLIST            12                t\r\n" );
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document.write( "BOTH TOTAL                                         12\r\n" );
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\n" ); document.write( "\n" ); document.write( "The two meet when the sum of their distances traveled becomes 12 miles.\r
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document.write( "                   rate             time          distance\r\n" );
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document.write( "JOGGER              6               t+1          6(t+1)\r\n" );
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document.write( "CYCLIST            12                t           12t\r\n" );
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document.write( "BOTH TOTAL                                         12\r\n" );
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\n" ); document.write( "\n" ); document.write( "\"highlight%286%28t%2B1%29%2B12t=12%29\"
\n" ); document.write( "Solve for t, quantity in hours.
\n" ); document.write( "This t is the number of hours past 8:00AM when the jogger and the cyclist meet.\r
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\n" ); document.write( "\n" ); document.write( "SOLUTION STEPS FOR THE EQUATION
\n" ); document.write( "\"6t%2B6%2B12t=12\"
\n" ); document.write( "\"18t%2B6=12\"
\n" ); document.write( "\"18t=6\"
\n" ); document.write( "\"t=6%2F18\"
\n" ); document.write( "\"highlight%28t=1%2F3%29\", which is 20 minutes.\r
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\n" ); document.write( "\n" ); document.write( "They meet at 9:20AM. \n" ); document.write( "
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