document.write( "Question 1024815: solve the equation on the interval [0,2pi]\r
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Algebra.Com's Answer #640199 by ikleyn(52790)\"\" \"About 
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document.write( "\"tan%5E2%28x%29\" = \"tan%5E2%28x%29%2Asec%28x%29\"  --->\r\n" );
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document.write( "\"tan%5E2%28x%29\" - \"tan%5E2%28x%29%2Asec%28x%29\" = \"0\",\r\n" );
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document.write( "\"tan%5E2%28x%29%2A%281-sec%28x%29%29\" = \"0\".\r\n" );
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document.write( "So this equations breaks down into two independent equations\r\n" );
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document.write( "1.  \"tan%5E2%28x%29\" = \"0\"  --->  tan(x) = 0  --->  x = 0 and x = \"pi\".\r\n" );
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document.write( "2.  \"1-sec%28x%29\" = \"0\"  ---> \"1+-+1%2Fcos%28x%29\" = 0  --->  cos(x) = 1  --->  x = 0. \r\n" );
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document.write( "The entire set of solution of the original equation in the given interval consists of two numbers:  0  and  \"pi\".\r\n" );
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