document.write( "Question 1024839: Only 35% of the drivers in a particular city wear seat belts. Suppose that 20 drivers are stopped at random what is the probability that exactly four are wearing a seatbelt? (Round your answer to 4 decimal places) \n" ); document.write( "
Algebra.Com's Answer #640198 by mathmate(429)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Question: \n" ); document.write( "Only 35% of the drivers in a particular city wear seat belts. Suppose that 20 drivers are stopped at random what is the probability that exactly four are wearing a seatbelt? (Round your answer to 4 decimal places) \n" ); document.write( " \n" ); document.write( "Solution: \n" ); document.write( "Here we have a situation where the probability of a driver wearing seat belts is known and remains constant throughout the experiment of stopping 20 drivers. \n" ); document.write( "The drivers stopped are assumed to be random and independent. \n" ); document.write( "These conditions are suitable for modelling using he binomial distribution, where \n" ); document.write( "P(X=x)= \n" ); document.write( "where n=number of drivers stopped (sample size = 20) \n" ); document.write( "x=number of drivers wearing seatbelts (4) \n" ); document.write( "p=probability that a driver wears seatbelts (0.35), and \n" ); document.write( "C(n,x)=binomial coefficient of x objects chosen from n = n!/(x!(n-x)!) \n" ); document.write( " \n" ); document.write( "So the probability of finding 4 drivers wearing seatbelts out of a sample of 20 \n" ); document.write( "P(4;20;0.35) \n" ); document.write( "=C(20,4)*(0.35)^4*(0.65)^16 \n" ); document.write( "= 4845*0.0150061*0.0010153 \n" ); document.write( "= 0.07382 \n" ); document.write( " |