document.write( "Question 1024839: Only 35% of the drivers in a particular city wear seat belts. Suppose that 20 drivers are stopped at random what is the probability that exactly four are wearing a seatbelt? (Round your answer to 4 decimal places) \n" ); document.write( "
Algebra.Com's Answer #640198 by mathmate(429)\"\" \"About 
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\n" ); document.write( "Question:
\n" ); document.write( "Only 35% of the drivers in a particular city wear seat belts. Suppose that 20 drivers are stopped at random what is the probability that exactly four are wearing a seatbelt? (Round your answer to 4 decimal places)
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\n" ); document.write( "Solution:
\n" ); document.write( "Here we have a situation where the probability of a driver wearing seat belts is known and remains constant throughout the experiment of stopping 20 drivers.
\n" ); document.write( "The drivers stopped are assumed to be random and independent.
\n" ); document.write( "These conditions are suitable for modelling using he binomial distribution, where
\n" ); document.write( "P(X=x)=\"C%28n%2Cx%29%2Ap%5Ex%2A%281-p%29%5E%28n-x%29\"
\n" ); document.write( "where n=number of drivers stopped (sample size = 20)
\n" ); document.write( "x=number of drivers wearing seatbelts (4)
\n" ); document.write( "p=probability that a driver wears seatbelts (0.35), and
\n" ); document.write( "C(n,x)=binomial coefficient of x objects chosen from n = n!/(x!(n-x)!)
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\n" ); document.write( "So the probability of finding 4 drivers wearing seatbelts out of a sample of 20
\n" ); document.write( "P(4;20;0.35)
\n" ); document.write( "=C(20,4)*(0.35)^4*(0.65)^16
\n" ); document.write( "= 4845*0.0150061*0.0010153
\n" ); document.write( "= 0.07382
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