document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1024786>Question 1024786</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given:ABCD is a parallelogram, DE is perpendicular to AC and BF is also perpendicular to AC. Prove AE is congruent to FC </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #640155 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=640155\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "Given:ABCD is a parallelogram, DE is perpendicular to AC and BF is also perpendicular to AC. Prove AE is congruent to FC<BR>\n" );
document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Use the fact that the diagonal of the parallelogram divides it in two congruent triangle.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Hence, the triangles ACB and ACD have the same area.\r<BR>\n" );
document.write( "\n" );
document.write( "They also have the common base AC.\r<BR>\n" );
document.write( "\n" );
document.write( "Therefore, the altitudes of these triangles, AE and FC, are congruent.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );