document.write( "Question 1024759: (2/3 p to the power of 4 y cubic) ( y to the power of 4 s to the power of 5) ( 6 p squared s cube) \n" ); document.write( "

Algebra.Com's Answer #640139 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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(2/3 p to the power of 4 y cubic) ( y to the power of 4 s to the power of 5) ( 6 p squared s cube)
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\n" ); document.write( " $\"%28%282%2F3%29p%5E4y%5E3%29%28y%5E4s%5E5%29%286p%5E2s%5E3%29\"$
\n" ); document.write( "we don't need the brackets
\n" ); document.write( " $\"%282%2F3%29p%5E4y%5E3y%5E4s%5E5%2A6p%5E2s%5E3\"$
\n" ); document.write( "group like terms
\n" ); document.write( " $\"%282%2F3%29p%5E4%2A6p%5E2%2Ay%5E3%2Ay%5E4%2As%5E5%2As%5E3\"$
\n" ); document.write( "2/3 of 6 is 4, add the exponents of like terms so we have
\n" ); document.write( " $\"4p%5E6%2Ay%5E7%2As%5E8\"$
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