document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1024747>Question 1024747</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if we join the bases of 2 identical cylindrical tubes. the height of each tube is 15 cm and the diameter is 6 cm. what will be the surface area of new shape? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #640137 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=640137\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 15+15 = h (height of new cylinder)<BR>\n" );
document.write( "6*Pi = perimeter of the circumference (the tube)<BR>\n" );
document.write( "(6*Pi)*(15+15)= area of the tube <BR>\n" );
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document.write( "Note: surface area of the open tube, without caps at the ends. If you want caps at the ends, to the result you get you have to add:(6/2)^2*Pi, or you can do it this way:(Pi/4)*6^2<BR>\n" );
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document.write( "Practice using your calculator.<BR>\n" );
document.write( "J<BR>\n" );
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