document.write( "Question 1024705: A researcher reports survey results by stating that the standard error of the mean is 20. The population standard deviation is 500.\r
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document.write( "a) How large was the sample used in this survey?
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document.write( "b) What is the probability that the point estimate was within ±25 of the population mean? \r
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document.write( "Answers:
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document.write( "a) 625
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document.write( "b) 0.7888 \n" );
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Algebra.Com's Answer #640125 by Theo(13342)![]() ![]() You can put this solution on YOUR website! sd = 500 \n" ); document.write( "se = 20 \n" ); document.write( "n = sample size\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula for standard error of the mean is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "se = sd / sqrt(n)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "se = 20 \n" ); document.write( "sd = 500\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "formula becomes 20 = 500 / sqrt(n).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for sqrt(n) to get sqrt(n) = 500 / 20 = 25.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for n to get n = 25^2 = 625.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula for z-score is z = (x-m) / se.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-m) is equal to plus or minus 25. \n" ); document.write( "se is equal to 20.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula for z-score becomes z = plus or minus 25/20.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this results in z-score = plus or minus 1.25.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "use a z-score calculator to find that the z-score between -1.25 and 1.25 has a probability of occurrence of .788...\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "these solutions agree with the answers provided to you.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you could assume the mean is any number. \n" ); document.write( "if the actual score is plus or minus 25 from that, you will get the same result. \n" ); document.write( "this assumes the standard error is 20.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for example:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "assume the mean is 5000. \n" ); document.write( "assume the actual score is 4975 or 5025.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the z-score formula becomes z = (5025 - 5000) / 20 = 25/20 = 1.25.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the z-score formula also becomes z = (4975 - 5000) / 20 = -25/20 = -1.25.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the z-wscore table between a z-score of -1.25 and 1.25 will tell you that the probbility of this occuring is .788....\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a picture of just what i told you.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this solution depends on the standard error of the mean being 20.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "as an additional note, the standard error of the mean is equal to the standard deviation of the distribution of sample means from multiple samples of the same sample size.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |