document.write( "Question 1024736: A tangent to the parabola x2 = 4ay is inclined at an angle with the x-axis,find then coordinates of point of contact \n" ); document.write( "
Algebra.Com's Answer #640117 by josgarithmetic(39630)\"\" \"About 
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\"x%5E2=4ay\", or a better form with which to work, \"y=%281%2F%284a%29%29x%5E2\". The line or lines tangent to the parabola will have slope \"dy%2Fdx=%281%2F%284a%29%29%2A2x=%281%2F%282a%29%29x\".\r
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\n" ); document.write( "\n" ); document.write( "Any general point on the parabola is (x, (x^2)/(4a)).
\n" ); document.write( "Pick any of these points you like as long as \"x%3C%3E0\". Why? Because at x=0, the slope is 0, for a horizontal line, and will not make an angle with the x-axis. The question description specifies that the tangent line makes an angle with the x-axis.
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