document.write( "Question 1024741: log2(3X-1)-1=log2x \n" ); document.write( "

Algebra.Com's Answer #640108 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+log%28+2%2C+3x-1+%29+-+1++=+log%28+2%2C+x+%29+\"$
\n" ); document.write( "Use the identity:
\n" ); document.write( " $\"+1+=+log%28+2%2C2+%29+\"$
\n" ); document.write( "Now you have:
\n" ); document.write( " $\"+log%28+2%2C+3x-1+%29+-+log%28+2%2C2+%29++=+log%28+2%2C+x+%29+\"$
\n" ); document.write( " $\"+log%28+2%2C+%28+3x+-+1+%29%2F2+%29+=+log%28+2%2Cx+%29+\"$
\n" ); document.write( "if the logs are equal, the quantities are equal
\n" ); document.write( " $\"+%28+3x+-+1+%29%2F2+=+x+\"$
\n" ); document.write( " $\"+3x+-+1+=+2x+\"$
\n" ); document.write( " $\"+x+=+1+\"$
\n" ); document.write( "------------
\n" ); document.write( "check answer:
\n" ); document.write( " $\"+log%28+2%2C+3x-1+%29+-+1++=+log%28+2%2C+x+%29+\"$
\n" ); document.write( " $\"+log%28+2%2C+3%2A1-1+%29+-+1++=+log%28+2%2C1+%29+\"$
\n" ); document.write( " $\"+log%28+2%2C+2+%29+-+1+=+log%28+2%2C1+%29+\"$
\n" ); document.write( " $\"+1+-+1+=+0+\"$
\n" ); document.write( " $\"+0+=+0+\"$ \n" ); document.write( "

\n" );