document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=88170>Question 88170</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angles of a triangle have equal measures but the third angles measure is 36 degrees less than the sum of the other two . find the measure of each angle of the triangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64010 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64010\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = measure of one of the equal angles<BR>\n" );
document.write( "2x-36 = third angle\r<BR>\n" );
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document.write( "x + x + 2x-36 = 180<BR>\n" );
document.write( "4x - 36= 180<BR>\n" );
document.write( "4x -36+36= 180+36<BR>\n" );
document.write( "4x = 216<BR>\n" );
document.write( "x= 54 Degrees = Equal angles\r<BR>\n" );
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document.write( "2x-36 = 72 Degrees = Third angle\r<BR>\n" );
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document.write( "Check:  54+54+72= 180 degrees\r<BR>\n" );
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document.write( "R^2 </SPAN>\n" );
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