document.write( "Question 1024708:
\n" ); document.write( "How many liters of a 80​% acid solution must be mixed with a 15​% acid solution to get 455 L of a 70​% acid​ solution?
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Algebra.Com's Answer #640097 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
x of 80%;
\n" ); document.write( "455-x of 15%;\r
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\n" ); document.write( "\n" ); document.write( "\"%2880x%2B15%28455-x%29%29%2F455=70\";
\n" ); document.write( "Solve for x and that is how much liters of the 80%; and by difference get the 15%.\r
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\n" ); document.write( "\n" ); document.write( "You can also do this using two variables.
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