document.write( "Question 1024708:
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document.write( "How many liters of a 80% acid solution must be mixed with a 15% acid solution to get 455 L of a 70% acid solution? \n" );
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Algebra.Com's Answer #640097 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! x of 80%; \n" ); document.write( "455-x of 15%;\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Solve for x and that is how much liters of the 80%; and by difference get the 15%.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can also do this using two variables. \n" ); document.write( " |