document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1024720>Question 1024720</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a college athletic field is 100 meters and the length is 14 m more than the width. Find the length and width.<BR>\n" );
document.write( "What is the&#8203; width? \r<BR>\n" );
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document.write( "What is the&#8203; length?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #640091 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=640091\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a college athletic field is 100 meters and the length is 14 m more than the width. Find the length and width.<BR>\n" );
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document.write( "P = 2(L+W)<BR>\n" );
document.write( "100 = 2(W+14+W)<BR>\n" );
document.write( "2W + 14 = 50<BR>\n" );
document.write( "2W = 36<BR>\n" );
document.write( "Width = 18 m<BR>\n" );
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document.write( "Length = W+14 = 32 m<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( "What is the&#8203; width? <BR>\n" );
document.write( "What is the&#8203; length?<BR>\n" );
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