document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1024650>Question 1024650</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use polynomial remainder theorem to evaluate the polynomial for the given value<BR>\n" );
document.write( "f(X)-x to the power of 3-x to the power of 2-2x-5:f(-5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #640079 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=640079\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can use ^ for exponentiation, e.g.\r<BR>\n" );
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document.write( "f(x) = x^3 - x^2 - 2x - 5\r<BR>\n" );
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document.write( "Since f(x) can be written in the form (x+5)Q(x) + R for some constant R, the remainder can be computed by simply computing f(-5) (so that the equation becomes f(-5) = R). To compute f(-5), simply replace all x's with -5 and simplify. </SPAN>\n" );
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