document.write( "Question 1024656: If I was born on 8-1-1960 and my daughter was born on 8-8-1988 on what date will I be twice as old as her in number of days? \n" ); document.write( "
Algebra.Com's Answer #640045 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "The same number of calendar days and weeks pass every 4 \r\n" ); document.write( "years. 1988-1964 = 28. 28 years is an exact multiple of\r\n" ); document.write( "4-year periods, and since 8-8 is exactly 1 week from 8-1,\r\n" ); document.write( "you are exactly 28 years and 1 week older than your \r\n" ); document.write( "daughter. So you will be twice as old as your daughter \r\n" ); document.write( "when she is 28 years and 1 week old. That will be this \r\n" ); document.write( "year since 1988+28=2016. Your daughter will be 28 years \r\n" ); document.write( "and 1 week, 1 week after her birtday this year. That \r\n" ); document.write( "will be 8-15-2016. \r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |