document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1024559>Question 1024559</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How to solve this one? I'm confuse which one is the first and second number? Thank you. <BR>\n" );
document.write( "One number is 5 more than another number. If you add 9 to 2 times the first number, the result is 3 times the second number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #639951 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=639951\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have to label them yourself.<BR>\n" );
document.write( "Call x the first one and y the second one.<BR>\n" );
document.write( "Then we can write<BR>\n" );
document.write( "x = y + 5  and<BR>\n" );
document.write( "9 + 2x = 3y<BR>\n" );
document.write( "Now substitute in for x and get<BR>\n" );
document.write( "9 + 2(y+5) = 3y<BR>\n" );
document.write( "9 + 2y + 10 = 3y<BR>\n" );
document.write( "19 + 2y = 3y<BR>\n" );
document.write( "y = 19<BR>\n" );
document.write( "and then<BR>\n" );
document.write( "x = 24<BR>\n" );
document.write( "How's that? </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );