document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1024556>Question 1024556</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars leave Atlanta at the same time. One is traveling north and another is traveling south at a rate 5mph faster than the north-bound car. After 3 hours they are 495 miles apart. How fast is each traveling? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #639943 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=639943\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the slower car's rate, r.  The faster is moving at r+5.<BR>\n" );
document.write( "Now rate times time equals distance, or rt=d.<BR>\n" );
document.write( "The time is 3 hours for each car.<BR>\n" );
document.write( "Thus we can write<BR>\n" );
document.write( "3r + 3(r+5) = 495<BR>\n" );
document.write( "3r + 3r + 15 = 495<BR>\n" );
document.write( "6r + 15 = 495<BR>\n" );
document.write( "6r = 480<BR>\n" );
document.write( "r = 60 miles per hour<BR>\n" );
document.write( "r+5 = 65 miles per hour </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );