document.write( "Question 1024461: Find the nth degree polynomial function with real coefficients satisfying the given conditions. If you are using a graphing utility, use it to graph the function and verify the real zeros and the given function value. N=3; -2 and 5+4i are zeros; f (-1)=52 \n" ); document.write( "
Algebra.Com's Answer #639905 by Fombitz(32388)\"\" \"About 
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Since one of the roots is complex and it has real coefficients, the complex conjugate is also a root.
\n" ); document.write( "\"f%28x%29=a%28x%2B2%29%28x-%285%2B4i%29%29%28x-%285-4i%29%29\"
\n" ); document.write( "\"f%28x%29=a%28x%2B2%29%28x%5E2-10x%2B41%29\"
\n" ); document.write( "When \"x=-1\"
\n" ); document.write( "\"f%28-1%29=a%28-1%2B2%29%28-1%5E2%2B10%2B41%29\"
\n" ); document.write( "\"52=a%281%29%2852%29\"
\n" ); document.write( "\"a=1\"
\n" ); document.write( "So then,
\n" ); document.write( "\"f%28x%29=%28x%2B2%29%28x%5E2-10x%2B41%29\"
\n" ); document.write( "\"f%28x%29=x%5E3-8x%5E2%2B21x%2B82\"
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