document.write( "Question 88114: I can sure use some help on this please.
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Algebra.Com's Answer #63988 by malakumar_kos@yahoo.com(315) ![]() You can put this solution on YOUR website! \n" ); document.write( " the length of a rectangle is 2 in. more than twice its width. if the perimeter of the rectangle is 34 in, find the dimension of the rectangle\r \n" ); document.write( "\n" ); document.write( " Let the width of the rectangle be= b = 2x \n" ); document.write( " Then the length of the rectangle = l = 2x+2 \n" ); document.write( " The perimeter of the rectangle = p = 34 in \n" ); document.write( " p = 2(l+b) \n" ); document.write( " 34 = 2(2x+2+2x) \n" ); document.write( " 34/2= 4x+2 \n" ); document.write( " 17-2 = 4x \n" ); document.write( " 4x = 15 \n" ); document.write( " x = 15/4 = 3.75 \n" ); document.write( " The dimensions of the rectangle are b = 2(3.75) = 7.5 inch \n" ); document.write( " l = 2(3.75)+2 = 9.5 inch \n" ); document.write( " |