document.write( "Question 1024486: Solve by substitution method. x=2y+3 and 3x+5y=1
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Algebra.Com's Answer #639865 by ikleyn(52798)\"\" \"About 
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document.write( "x = 2y + 3,      (1)\r\n" );
document.write( "3x + 5y = 1.     (2)\r\n" );
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document.write( "You just have x expressed via y in the equation (1).\r\n" );
document.write( "So, simply substitute it for x into equation (2). You will get a single equation for y\r\n" );
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document.write( "3*(2y + 3) + 5y = 1.\r\n" );
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document.write( "Simplify and solve for y:\r\n" );
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document.write( "6y + 9 + 5y = 1,\r\n" );
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document.write( "11y = 1 - 9,\r\n" );
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document.write( "11y = -8,\r\n" );
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document.write( "y = \"-8%2F11\".  So, you just have y.\r\n" );
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document.write( "Now substitute it into (1) and find x.\r\n" );
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