document.write( "Question 1024408: The perimeter of a rectangle 40cm. The length is 2cm more than 5 times the width. What are the the dimensions. \n" ); document.write( "

Algebra.Com's Answer #639861 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "The perimeter of a rectangle 40cm. The length is 2cm more than 5 times the width. What are the the dimensions.
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document.write( "L + W = 20,   (1)\r\n" );
document.write( "L = 5W + 2.   (2)\r\n" );
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document.write( "Substitute (2) into (1). You will get\r\n" );
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document.write( "(5W + 2) + W = 20,   or\r\n" );
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document.write( "6W = 20 - 2,   or\r\n" );
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document.write( "6W = 18,\r\n" );
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document.write( "W =  = 3 cm. It is the width.\r\n" );
document.write( "The length is L = 5W + 2 = 5*3 + 2 = 17.\r\n" );
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