document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=88116>Question 88116</A>: <I><SPAN STYLE=\"word-break: break-all;\">  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #63985 by </B><A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><B>malakumar_kos@yahoo.com(315)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=63985\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "   When you have a problem like below how do you solve it? Do you have to solve twice so that you use x both times?\r<BR>\n" );
document.write( "\n" );
document.write( "Find the values of the following expression if x = - 3 and -2 <BR>\n" );
document.write( "-x^2-5x-6<BR>\n" );
document.write( "  We have to solve it twice taking  the values of x as -3 &-2<BR>\n" );
document.write( "1) First taking the value of x = -3  we get -x^2-5x-6 = -(-3)^2-5(-3)-6 <BR>\n" );
document.write( "                                                      = -(+9)+15-6<BR>\n" );
document.write( "                                                      =-9-6+15<BR>\n" );
document.write( "                                                      = -15+15<BR>\n" );
document.write( "                                                      = 0<BR>\n" );
document.write( " 2)taking the value of x=-2 we get -x^2-5x-6 = -(-2)^2-5(-2)-6<BR>\n" );
document.write( "                                             =-(4)+10-6<BR>\n" );
document.write( "                                             = -4-6+10<BR>\n" );
document.write( "                                             = 0 </SPAN>\n" );
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