document.write( "Question 1024324: A man walks 30 minutes at an average speed of 3km /hr. He waits 10 minutes for a bus, which brings him back to starting point at 3.15pm. If he began his walk at 2.25 pm the same afternoon, find the average speed. \n" ); document.write( "
Algebra.Com's Answer #639820 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A man walks 30 minutes at an average speed of 3km /hr. \n" ); document.write( " He waits 10 minutes for a bus, which brings him back to starting point at 3.15pm. \n" ); document.write( " If he began his walk at 2.25 pm the same afternoon, find the average speed. \n" ); document.write( ": \n" ); document.write( "Find the total time of the trip: 3:15 - 2:25 = 50 min; \n" ); document.write( "Find the distance to the bus stop: .5hrs * 3km/h = 1.5 km \n" ); document.write( "Round trip = 3km and we know it took 5/6 hr \n" ); document.write( "let a = the average speed of the trip \n" ); document.write( " \n" ); document.write( "cross multiply \n" ); document.write( "5a = 3 * 6 \n" ); document.write( "a = \n" ); document.write( "a = 3.6 km/hr average speed for the whole trip \n" ); document.write( " |