document.write( "Question 1024324: A man walks 30 minutes at an average speed of 3km /hr. He waits 10 minutes for a bus, which brings him back to starting point at 3.15pm. If he began his walk at 2.25 pm the same afternoon, find the average speed. \n" ); document.write( "
Algebra.Com's Answer #639820 by ankor@dixie-net.com(22740)\"\" \"About 
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A man walks 30 minutes at an average speed of 3km /hr.
\n" ); document.write( " He waits 10 minutes for a bus, which brings him back to starting point at 3.15pm.
\n" ); document.write( " If he began his walk at 2.25 pm the same afternoon, find the average speed.
\n" ); document.write( ":
\n" ); document.write( "Find the total time of the trip: 3:15 - 2:25 = 50 min; \"5%2F6\" hrs
\n" ); document.write( "Find the distance to the bus stop: .5hrs * 3km/h = 1.5 km
\n" ); document.write( "Round trip = 3km and we know it took 5/6 hr
\n" ); document.write( "let a = the average speed of the trip
\n" ); document.write( "\"3%2Fa\" = \"5%2F6\"
\n" ); document.write( "cross multiply
\n" ); document.write( "5a = 3 * 6
\n" ); document.write( "a = \"18%2F5\"
\n" ); document.write( "a = 3.6 km/hr average speed for the whole trip
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