document.write( "Question 88148: \n" ); document.write( "
Algebra.Com's Answer #63980 by malakumar_kos@yahoo.com(315) ![]() You can put this solution on YOUR website! \n" ); document.write( " a rectangular field is 4 times as long as it is wide . if the length is decreased by 10 in. and the width is increased by 2 in. the perimeter will be 80 in. find the dimensions of the original field \n" ); document.write( " \n" ); document.write( " Let the width of the field be = b =x in. \n" ); document.write( " the length of the field will be = l = 4x \n" ); document.write( " the new length of the field be =L = 4x-10 \n" ); document.write( " the new width of the field be = B = x+2 \n" ); document.write( " the perimeter of the field is = p = 80 \n" ); document.write( " perimeter = 2(L+B) \n" ); document.write( " p = 2(L+B) \n" ); document.write( " 80 = 2(4x-10+x+2) \n" ); document.write( " 80 = 2(5x-8) \n" ); document.write( " 80/2 = 5x-8 \n" ); document.write( " 40 = 5x-8 \n" ); document.write( " 5x = 40+8 = 48 \n" ); document.write( " x = 48/5 = 9.6 4x = 4.(9.6) = 38.4 \n" ); document.write( " length of the original field = 9.6 in \n" ); document.write( " width of the original field = 38.4 in \n" ); document.write( " |