document.write( "Question 88148: \n" ); document.write( "
Algebra.Com's Answer #63980 by malakumar_kos@yahoo.com(315)\"\" \"About 
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\n" ); document.write( " a rectangular field is 4 times as long as it is wide . if the length is decreased by 10 in. and the width is increased by 2 in. the perimeter will be 80 in. find the dimensions of the original field
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\n" ); document.write( " Let the width of the field be = b =x in.
\n" ); document.write( " the length of the field will be = l = 4x
\n" ); document.write( " the new length of the field be =L = 4x-10
\n" ); document.write( " the new width of the field be = B = x+2
\n" ); document.write( " the perimeter of the field is = p = 80
\n" ); document.write( " perimeter = 2(L+B)
\n" ); document.write( " p = 2(L+B)
\n" ); document.write( " 80 = 2(4x-10+x+2)
\n" ); document.write( " 80 = 2(5x-8)
\n" ); document.write( " 80/2 = 5x-8
\n" ); document.write( " 40 = 5x-8
\n" ); document.write( " 5x = 40+8 = 48
\n" ); document.write( " x = 48/5 = 9.6 4x = 4.(9.6) = 38.4
\n" ); document.write( " length of the original field = 9.6 in
\n" ); document.write( " width of the original field = 38.4 in
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