document.write( "Question 1024297: Log25-log3+log12 \n" ); document.write( "

Algebra.Com's Answer #639718 by stanbon(75887) $\"\"$ $\"About$

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Log25-log3+log12
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\n" ); document.write( "= log[25*12/3]
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\n" ); document.write( "= log[100]
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\n" ); document.write( "= 2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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