document.write( "Question 1024275: The lengths of rectangles A and B are both four times as long as their widths. The lengths of rectangle A is three times the length of rectangle B. If the difference in the perimeters is 16cm, find the dimensions of each rectangle.
\n" ); document.write( "Use simultaneous equations.
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Algebra.Com's Answer #639703 by josgarithmetic(39618)\"\" \"About 
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Rectangle A
\n" ); document.write( "\"L+and+w\"
\n" ); document.write( "\"L=4w\"
\n" ); document.write( "\"2L%2B2w=perimA\"\r
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\n" ); document.write( "\n" ); document.write( "Rectangle B
\n" ); document.write( "\"x+and+y\"
\n" ); document.write( "\"y=4x\"
\n" ); document.write( "\"2y%2B2x=perimB\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%28L=3y%2CperimA-perimB=16%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%28L=3y%2Cy=4x%2C2L%2B2w-%282y%2B2x%29=16%29\"
\n" ); document.write( "This seems to not be enough. Making the substitution for L and y, you would have one
\n" ); document.write( "equation but still two variables.
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