document.write( "Question 88136: \n" ); document.write( "
Algebra.Com's Answer #63968 by malakumar_kos@yahoo.com(315)\"\" \"About 
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\n" ); document.write( " one side of a rectangle is 3 less than the other side and the perimeter is 54 inches long what are the dimensions of the rectangle?
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\n" ); document.write( " Let the length of the rectangle be = l = x inc
\n" ); document.write( " the width of the rectangle will be = b = x-3 inc
\n" ); document.write( " perimeter of the rectangle is = p = 54 inc\r
\n" ); document.write( "\n" ); document.write( " p = 2(l+b)
\n" ); document.write( " 54 = 2(x+x-3)
\n" ); document.write( " 54/2 = 2x-3
\n" ); document.write( " 27 = 2x-3 or 27+3 = 2x i.e, 2x = 30
\n" ); document.write( " x= 30/2 = 15\r
\n" ); document.write( "\n" ); document.write( " length of the rectangle = l = 15 inch
\n" ); document.write( " width of the rectangle = b = 15-3 = 12 inch
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