document.write( "Question 88136: \n" ); document.write( "
Algebra.Com's Answer #63968 by malakumar_kos@yahoo.com(315) ![]() You can put this solution on YOUR website! \n" ); document.write( " one side of a rectangle is 3 less than the other side and the perimeter is 54 inches long what are the dimensions of the rectangle? \n" ); document.write( " \n" ); document.write( " Let the length of the rectangle be = l = x inc \n" ); document.write( " the width of the rectangle will be = b = x-3 inc \n" ); document.write( " perimeter of the rectangle is = p = 54 inc\r \n" ); document.write( "\n" ); document.write( " p = 2(l+b) \n" ); document.write( " 54 = 2(x+x-3) \n" ); document.write( " 54/2 = 2x-3 \n" ); document.write( " 27 = 2x-3 or 27+3 = 2x i.e, 2x = 30 \n" ); document.write( " x= 30/2 = 15\r \n" ); document.write( "\n" ); document.write( " length of the rectangle = l = 15 inch \n" ); document.write( " width of the rectangle = b = 15-3 = 12 inch \n" ); document.write( " \n" ); document.write( " |