document.write( "Question 1024206: The perimeter of a rectangle is 500 yards. What are the dimensions of the rectangle if the length is 90 yards more than the​ width?
\n" ); document.write( "The length is
\n" ); document.write( "3535 yards and the width is
\n" ); document.write( "nothing yards.
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Algebra.Com's Answer #639649 by josgarithmetic(39617)\"\" \"About 
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w and L for width and length;
\n" ); document.write( "\"system%28L=w%2B90%2C2w%2B2L=500%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2w%2B2%28w%2B90%29=500\"
\n" ); document.write( "Find w, first.....
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