document.write( "Question 1024155: Predict the population of bacteria for each situation and time period. This is exponential growth. Can you help me solve for A and B?\r
\n" ); document.write( "\n" ); document.write( "1) 55 bacteria that double every hour after:
\n" ); document.write( "A) after 3 hours B) after 5 hours. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2) 33 bacteria that double every 30 minutes
\n" ); document.write( "A) after 1 hour B) after 6 hours.
\n" ); document.write( "

Algebra.Com's Answer #639610 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Predict the population of bacteria for each situation and time period. This is exponential growth. Can you help me solve for A and B?\r
\n" ); document.write( "\n" ); document.write( "1) 55 bacteria that double every hour after:
\n" ); document.write( "A) after 3 hours
\n" ); document.write( "> 1 hour = 55*2 = 110
\n" ); document.write( "> 2 hour = 110*2 = 220
\n" ); document.write( "> 1 hour = 220*2 = 440
\n" ); document.write( "--> 55*2^t, t in hours
\n" ); document.write( "---
\n" ); document.write( "B) after 5 hours
\n" ); document.write( "55*2^5 = 1760
\n" ); document.write( "======================\r
\n" ); document.write( "\n" ); document.write( "2) 33 bacteria that double every 30 minutes
\n" ); document.write( "A) after 1 hour
\n" ); document.write( "= 33*2^t, t in 30 min periods
\n" ); document.write( "= 33*2^2 = 132
\n" ); document.write( "----------
\n" ); document.write( "B) after 6 hours
\n" ); document.write( "6 hrs = 12 periods
\n" ); document.write( "= 33*2^12
\n" ); document.write( "= 135168
\n" ); document.write( "
\n" );