document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1024133>Question 1024133</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A scientist has two solutions which she has labeled solution a and solution B you can seem so she knows that solution a is 25% salt solution that is 75% salt she wants to obtain a 90 ounce of a mixture that is 35% salt how many ounces of each solution will she need </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #639599 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=639599\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the amount of 25% solution, x.  Then the amount of 75% solution would have to be 90-x.  The setup is like this...<BR>\n" );
document.write( ".25x + .75(90-x) = .35(90)<BR>\n" );
document.write( "Now solve this...<BR>\n" );
document.write( ".25x + 67.5 - .75x = 31.5<BR>\n" );
document.write( "-.5x = -36<BR>\n" );
document.write( "x = 72 ounces of 25% solution which means<BR>\n" );
document.write( "90-x = 18 ounces of 75% solution </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );