document.write( "Question 1024071: A rectangle has a length twice it's width, and area 288cm squared, what is the perimeter?\r
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document.write( "I have tried square rooting but I don't know if it's right. \n" );
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Algebra.Com's Answer #639536 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Make the width = 'x' \n" ); document.write( "Length then = 2x \n" ); document.write( "Area = Width x Length \n" ); document.write( "288 = x(2x) \n" ); document.write( "2x^2 = 288 \n" ); document.write( "x^2 = 144 \n" ); document.write( "x = 12 \n" ); document.write( "Width = 12 cm (x) \n" ); document.write( "Length = 24 cm (2x) \n" ); document.write( "Perimeter = 2(Width) + 2(Length) \n" ); document.write( "Perimeter = 2(12) + 2(24) \n" ); document.write( "Perimeter = 24 + 48 \n" ); document.write( "Perimeter = 72 cm. \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |