document.write( "Question 1024071: A rectangle has a length twice it's width, and area 288cm squared, what is the perimeter?\r
\n" ); document.write( "\n" ); document.write( "I have tried square rooting but I don't know if it's right.
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Algebra.Com's Answer #639536 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,
\n" ); document.write( "Make the width = 'x'
\n" ); document.write( "Length then = 2x
\n" ); document.write( "Area = Width x Length
\n" ); document.write( "288 = x(2x)
\n" ); document.write( "2x^2 = 288
\n" ); document.write( "x^2 = 144
\n" ); document.write( "x = 12
\n" ); document.write( "Width = 12 cm (x)
\n" ); document.write( "Length = 24 cm (2x)
\n" ); document.write( "Perimeter = 2(Width) + 2(Length)
\n" ); document.write( "Perimeter = 2(12) + 2(24)
\n" ); document.write( "Perimeter = 24 + 48
\n" ); document.write( "Perimeter = 72 cm.
\n" ); document.write( "Hope this helps :-)
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