document.write( "Question 1023988: A lab needs to make 100 gallons of an 18% acid solution by mixing a 12% acid\r
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Algebra.Com's Answer #639483 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
v gallons of the 20% acid and 100-v gallons of the 12% acid. Concentration wanted is 18%.\r
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\n" ); document.write( "\n" ); document.write( "\"%2812%28100-v%29%2B20v%29%2F100=18\"\r
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\n" ); document.write( "\n" ); document.write( "--
\n" ); document.write( "some steps....\r
\n" ); document.write( "\n" ); document.write( "\"12%28100-v%29%2B20v=18%2A100\"\r
\n" ); document.write( "\n" ); document.write( "\"6%28100-v%29%2B10v=9%2A100\"\r
\n" ); document.write( "\n" ); document.write( "\"3%28100-v%29%2B5v=9%2A50\"\r
\n" ); document.write( "\n" ); document.write( "\"300-3v%2B5v=9%2A50\"\r
\n" ); document.write( "\n" ); document.write( "keep going until solved.....
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