document.write( "Question 1023988: A lab needs to make 100 gallons of an 18% acid solution by mixing a 12% acid\r
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document.write( "solution with a 20% solution. How many gallons of each solution are needed? \n" );
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Algebra.Com's Answer #639482 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A lab needs to make 100 gallons of an 18% acid solution by mixing a 12% acid \n" ); document.write( "solution with a 20% solution. How many gallons of each solution are needed? \n" ); document.write( "----------------------- \n" ); document.write( "Quantity:: t + w = 100 gallons \n" ); document.write( "Acid Eq:: 0.12t + 0.20w = 0.18*100 \n" ); document.write( "---------------------------------------- \n" ); document.write( "Modify for elimination:: \n" ); document.write( "12t + 12w = 12*100 \n" ); document.write( "12t + 20w = 18*100 \n" ); document.write( "------------- \n" ); document.write( "Subtract and solve for \"w\":: \n" ); document.write( "8w = 6*100 \n" ); document.write( "----- \n" ); document.write( "w = 75 gallons (amt. of 20% solution needed) \n" ); document.write( "------------ \n" ); document.write( "Solve for \"t\":: \n" ); document.write( "t = 100 - 75 = 25 gallons (amt. of 12% solution needed) \n" ); document.write( "----------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "--------------- \n" ); document.write( " |