document.write( "Question 1023988: A lab needs to make 100 gallons of an 18% acid solution by mixing a 12% acid\r
\n" ); document.write( "\n" ); document.write( "solution with a 20% solution. How many gallons of each solution are needed?
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Algebra.Com's Answer #639482 by stanbon(75887)\"\" \"About 
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A lab needs to make 100 gallons of an 18% acid solution by mixing a 12% acid
\n" ); document.write( "solution with a 20% solution. How many gallons of each solution are needed?
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\n" ); document.write( "Quantity:: t + w = 100 gallons
\n" ); document.write( "Acid Eq:: 0.12t + 0.20w = 0.18*100
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\n" ); document.write( "Modify for elimination::
\n" ); document.write( "12t + 12w = 12*100
\n" ); document.write( "12t + 20w = 18*100
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\n" ); document.write( "Subtract and solve for \"w\"::
\n" ); document.write( "8w = 6*100
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\n" ); document.write( "w = 75 gallons (amt. of 20% solution needed)
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\n" ); document.write( "Solve for \"t\"::
\n" ); document.write( "t = 100 - 75 = 25 gallons (amt. of 12% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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