document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1023944>Question 1023944</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3 times a number is 54 less than the square of that number. Find the positive solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #639452 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=639452\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's call the number, x.  Then we write<BR>\n" );
document.write( "3x = x^2 - 54<BR>\n" );
document.write( "Subtract off the 3x and then factor...we get<BR>\n" );
document.write( "x^2 - 3x - 54 = 0<BR>\n" );
document.write( "(x - 9)(x + 6) = 0<BR>\n" );
document.write( "x = 9  or   x = -6<BR>\n" );
document.write( "The positive solution is<BR>\n" );
document.write( "x = 9 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );