document.write( "Question 1023928: Find 3 consecutive positive even integers such that 4 times the first decreased by the second is 12 more than twice the third. \n" ); document.write( "
Algebra.Com's Answer #639440 by LinnW(1048)![]() ![]() You can put this solution on YOUR website! X the first number \n" ); document.write( "X + 1 the second number \n" ); document.write( "X + 2 the third number \n" ); document.write( "4X -(X+1) = 12 + 2(X+2) \n" ); document.write( "4X -X -1 = 12 + 2X + 4 \n" ); document.write( "3X -1 = 16 + 2X \n" ); document.write( "add 1 to each side \n" ); document.write( "3X = 17 + 2X \n" ); document.write( "add -2X to each side \n" ); document.write( "X = 17 \n" ); document.write( "So the numbers are 17 18 19 \n" ); document.write( "Verify by substituing in 4X -(X+1) = 12 + 2(X+2) \n" ); document.write( "4(17) -18 = 12 + 2(19) \n" ); document.write( "68 - 18 ?= 12 + 38 \n" ); document.write( "40 = 40 \n" ); document.write( " |