document.write( "Question 1023928: Find 3 consecutive positive even integers such that 4 times the first decreased by the second is 12 more than twice the third. \n" ); document.write( "
Algebra.Com's Answer #639440 by LinnW(1048)\"\" \"About 
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X the first number
\n" ); document.write( "X + 1 the second number
\n" ); document.write( "X + 2 the third number
\n" ); document.write( "4X -(X+1) = 12 + 2(X+2)
\n" ); document.write( "4X -X -1 = 12 + 2X + 4
\n" ); document.write( "3X -1 = 16 + 2X
\n" ); document.write( "add 1 to each side
\n" ); document.write( "3X = 17 + 2X
\n" ); document.write( "add -2X to each side
\n" ); document.write( "X = 17
\n" ); document.write( "So the numbers are 17 18 19
\n" ); document.write( "Verify by substituing in 4X -(X+1) = 12 + 2(X+2)
\n" ); document.write( "4(17) -18 = 12 + 2(19)
\n" ); document.write( "68 - 18 ?= 12 + 38
\n" ); document.write( "40 = 40
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