document.write( "Question 1023907: Find the equation of the regression line for the given data. Then construct a scatter plot of the data and draw the regression line. (The pair of variables have a significant correlation.) Then use the regression equation to predict the value of y for each of the given x-values, if meaningful. The number of hours 6 students spent for a test and their scores on that test are shown below.\r
\n" ); document.write( "\n" ); document.write( "Hours spent studying, x: 0,2,3,3,4,5
\n" ); document.write( "Test scores, y:41,46,49,45,65,69\r
\n" ); document.write( "\n" ); document.write( "a) x= 2 hours
\n" ); document.write( "b) x= 2.5 hours
\n" ); document.write( "c) x= 15 hours
\n" ); document.write( "d) x= 3.5 hours\r
\n" ); document.write( "\n" ); document.write( "Find the regression equation.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #639407 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


\n" );
document.write( "Hi
\n" );
document.write( "x       y   
\n" );
document.write( "0	41    
\n" );
document.write( "2	46
\n" );
document.write( "3	49
\n" );
document.write( "3	45
\n" );
document.write( "4	65
\n" );
document.write( "5	69
\n" );
document.write( "  y = 5.8315x + 35.978  (Excel scatter plot...Format:  Trendline/formula
\n" );
document.write( "a) x= 2 hours  y = 5.8315(2) + 35.978
\n" );
document.write( " b) x= 2.5 hours y = 5.8315(2.5) + 35.978
\n" );
document.write( " c) x= 15 hours  y = 5.8315(15) + 35.978
\n" );
document.write( " d) x= 3.5 hours  y = 5.8315(3.5) + 35.978
\n" );
document.write( "     .
\n" );
document.write( " \n" );
document.write( "

\n" );