document.write( "Question 1023909: THIS IS AN ALGEBRAIC FUNCTIONS VARIATIONS PROBLEM. There is also a constant k that is part of the equation I have to create. Can someone go through the logic for this problem? \r
\n" ); document.write( "\n" ); document.write( "Kepler's Third Law states that the square of time T required for a planet to complete one orbit around the sun (the period, that is, the length of one planetary year) is directly proportional to the cube of average distance d of the planet from the sun. For the planet Earth, assume d = 93 x 10^6 miles an T = 365 days. Find a) the period of Mars, given that Mars is approximately 1.5 times as distant from the sun as Earth; b) the average distance of Venus from the sun, given that the period of Venus is approximately 223 Earth days. \r
\n" ); document.write( "\n" ); document.write( "The units for Part a are in days and the units for part b are in miles.
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Algebra.Com's Answer #639405 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
...the square of time T required for a planet to complete one orbit around the sun (the period, that is, the length of one planetary year) is directly proportional to the cube of average distance d of the planet from the sun. \r
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\n" ); document.write( "\n" ); document.write( "The phrase, \"is directly proportional to...\" becomes \"something=k%2Asomeother\".\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28T%5E2=k%2Ad%5E3%29\"\r
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\n" ); document.write( "\n" ); document.write( "For the rest, solve for k and use the data to evaluate k and answer the last question.
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