document.write( "Question 1023891:
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document.write( "Jen Butler has been pricing Speed-Pass train fares for a group trip to New York. Three adults and four children must pay
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document.write( "$ 99.$99.
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document.write( "Two adults and three children must pay
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document.write( "$ 70.$70.
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document.write( "Find the price of the adult's ticket and the price of a child's ticket.\r
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document.write( "The price of a child's ticket is
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Algebra.Com's Answer #639401 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Call the prices of adult and children's tickets, a and c. Then we can write \n" ); document.write( "3a + 4c = 99 and \n" ); document.write( "2a + 3c = 70 \n" ); document.write( "Multiply the top one by 2 and the bottom one by three and subtract them...we get \n" ); document.write( "6a + 8c = 198 \n" ); document.write( "-(6a + 9c = 210) \n" ); document.write( "------------------ \n" ); document.write( "-c = -12 \n" ); document.write( "c = 12 ($12 for a child's ticket) \n" ); document.write( "Now substitute that into the top equation and get \n" ); document.write( "3a + 4(12) = 99 \n" ); document.write( "3a + 48 = 99 \n" ); document.write( "3a = 51 \n" ); document.write( "a = 17 ($17 for an adult ticket) \n" ); document.write( " |