document.write( "Question 1023891:
\n" ); document.write( "Jen Butler has been pricing​ Speed-Pass train fares for a group trip to New York. Three adults and four children must pay
\n" ); document.write( "$ 99.$99.  
\n" ); document.write( "Two adults and three children must pay
\n" ); document.write( "$ 70.$70.  
\n" ); document.write( "Find the price of the​ adult's ticket and the price of a​ child's ticket.\r
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\n" ); document.write( "\n" ); document.write( "The price of a​ child's ticket is
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Algebra.Com's Answer #639401 by fractalier(6550)\"\" \"About 
You can put this solution on YOUR website!
Call the prices of adult and children's tickets, a and c. Then we can write
\n" ); document.write( "3a + 4c = 99 and
\n" ); document.write( "2a + 3c = 70
\n" ); document.write( "Multiply the top one by 2 and the bottom one by three and subtract them...we get
\n" ); document.write( "6a + 8c = 198
\n" ); document.write( "-(6a + 9c = 210)
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\n" ); document.write( "-c = -12
\n" ); document.write( "c = 12 ($12 for a child's ticket)
\n" ); document.write( "Now substitute that into the top equation and get
\n" ); document.write( "3a + 4(12) = 99
\n" ); document.write( "3a + 48 = 99
\n" ); document.write( "3a = 51
\n" ); document.write( "a = 17 ($17 for an adult ticket)
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