document.write( "Question 12601: How many gallons of pure antifreeze must be added to 20 gallons of 25% antifreeze to get a mixture that is 40% antifreeze \n" ); document.write( "
Algebra.Com's Answer #6394 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Let x = amt of pure antifreeze to be added\r
\n" ); document.write( "\n" ); document.write( "You are adding this to 20 gallons of 25% and you will end up a total mixture of x+ 20 at 40%.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The equation is
\n" ); document.write( ".25(20) + x = .40(x+20)
\n" ); document.write( "5 + 1.00x = .40x + 8
\n" ); document.write( "1.00x - .40x = 8 - 5
\n" ); document.write( ".60x = 3\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+3%2F.6+=+30%2F6+=+5+gallons\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Does it check?? (It is VERY late in Florida, here! I don't guarantee my work or my spelling at this hour!!}}}\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "R^2 at SCC
\n" ); document.write( "
\n" ); document.write( "
\n" );