document.write( "Question 12601: How many gallons of pure antifreeze must be added to 20 gallons of 25% antifreeze to get a mixture that is 40% antifreeze \n" ); document.write( "
Algebra.Com's Answer #6394 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Let x = amt of pure antifreeze to be added\r \n" ); document.write( "\n" ); document.write( "You are adding this to 20 gallons of 25% and you will end up a total mixture of x+ 20 at 40%.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The equation is \n" ); document.write( ".25(20) + x = .40(x+20) \n" ); document.write( "5 + 1.00x = .40x + 8 \n" ); document.write( "1.00x - .40x = 8 - 5 \n" ); document.write( ".60x = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Does it check?? (It is VERY late in Florida, here! I don't guarantee my work or my spelling at this hour!!}}}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " \n" ); document.write( " |