document.write( "Question 1023822: when cot a = 2/5 and cos b = -3/5 find cos(a+b) \n" ); document.write( "
| Algebra.Com's Answer #639389 by Alan3354(69443)     You can put this solution on YOUR website! when cot a = 2/5 and cos b = -3/5 find cos(a+b) \n" ); document.write( "---------- \n" ); document.write( "Angle A could be in Q1 or Q3, not specified. \n" ); document.write( "---- \n" ); document.write( "Find sin(A) & cos(A): \n" ); document.write( "tan = 1/cot \n" ); document.write( "tan(A) = y/x = 5/2 \n" ); document.write( "r = sqrt(5^2+2^2) = sqrt(29) \n" ); document.write( "cos = x/r \n" ); document.write( "cos(A) = 2sqrt(29)/29 \n" ); document.write( "sin = sqrt(1 - cos^2) \n" ); document.write( "sin(A) = sqrt(783)/29 = 3sqrt(87)/29 \n" ); document.write( "--- \n" ); document.write( "Find sin(B) \n" ); document.write( "sin = sqrt(1 - cos^2) \n" ); document.write( "sin(B) = 4/5 \n" ); document.write( "Here again, B could be in Q2 or Q3, not given. \n" ); document.write( "------- \n" ); document.write( "cos(A+B) = cos(A)cos(B) - sin(A)sin(B) \n" ); document.write( "= (2sqrt(29)/29)*(-3/5) - (3sqrt(87)/29)*(4/5) \n" ); document.write( "= \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |