document.write( "Question 1023729: When you're 3/4 your age, I am 4x yours. When you are my age our total equals 140. \n" ); document.write( "
Algebra.Com's Answer #639366 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! When you're 3/4 your age, I am 4x yours. When you are my age our total equals 140. \n" ); document.write( ": \n" ); document.write( "a = your age \n" ); document.write( "b = my age \n" ); document.write( "let d = (b-a) the difference in our ages \n" ); document.write( ": \n" ); document.write( "When you're 3/4 your age, I am 4x yours \n" ); document.write( " d = 4( \n" ); document.write( " d = 3( \n" ); document.write( " d = \n" ); document.write( "replace d with (b-a) \n" ); document.write( "b - a = \n" ); document.write( "multiply by 4 \n" ); document.write( "4(b-a) = 9a \n" ); document.write( "4b - 4a = 9a \n" ); document.write( "4b = 9a + 4a \n" ); document.write( "4b = 13a \n" ); document.write( "b = \n" ); document.write( "b = 3.25a \n" ); document.write( ": \n" ); document.write( "\"When you are my age our total equals 140. \" \n" ); document.write( "a + d + b + d = 140 \n" ); document.write( "replace d with (b-a) \n" ); document.write( "a +(b-a) + b +(b-a) = 140 \n" ); document.write( "3b - a = 140 \n" ); document.write( "replace b with 3.25a \n" ); document.write( "3(3.25a) - a = 140 \n" ); document.write( "9.75a - a = 140 \n" ); document.write( "8.75a = 140 \n" ); document.write( "a = 140/8.75 \n" ); document.write( "a = 16 yrs is your age \n" ); document.write( "Find b \n" ); document.write( "b = 3.25*16 \n" ); document.write( "b = 52 yrs is my age \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "lets see if that works out \n" ); document.write( "\"When you are my age our total equals 140. \" \n" ); document.write( "52 - 16 = 36 yrs, the difference in our ages \n" ); document.write( "When your(a) age is 52, I(b) will be: 52 + 36 = 88. 88 + 52 = 140 \n" ); document.write( " \n" ); document.write( " |