document.write( "Question 1023729: When you're 3/4 your age, I am 4x yours. When you are my age our total equals 140. \n" ); document.write( "
Algebra.Com's Answer #639366 by ankor@dixie-net.com(22740)\"\" \"About 
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When you're 3/4 your age, I am 4x yours. When you are my age our total equals 140.
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\n" ); document.write( "a = your age
\n" ); document.write( "b = my age
\n" ); document.write( "let d = (b-a) the difference in our ages
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\n" ); document.write( "When you're 3/4 your age, I am 4x yours
\n" ); document.write( " d = 4(\"3%2F4\"a) - \"3%2F4\"a
\n" ); document.write( " d = 3(\"3%2F4\"a)
\n" ); document.write( " d = \"9%2F4\"a
\n" ); document.write( "replace d with (b-a)
\n" ); document.write( "b - a = \"9%2F4\"a
\n" ); document.write( "multiply by 4
\n" ); document.write( "4(b-a) = 9a
\n" ); document.write( "4b - 4a = 9a
\n" ); document.write( "4b = 9a + 4a
\n" ); document.write( "4b = 13a
\n" ); document.write( "b = \"13%2F4\"a
\n" ); document.write( "b = 3.25a
\n" ); document.write( ":
\n" ); document.write( "\"When you are my age our total equals 140. \"
\n" ); document.write( "a + d + b + d = 140
\n" ); document.write( "replace d with (b-a)
\n" ); document.write( "a +(b-a) + b +(b-a) = 140
\n" ); document.write( "3b - a = 140
\n" ); document.write( "replace b with 3.25a
\n" ); document.write( "3(3.25a) - a = 140
\n" ); document.write( "9.75a - a = 140
\n" ); document.write( "8.75a = 140
\n" ); document.write( "a = 140/8.75
\n" ); document.write( "a = 16 yrs is your age
\n" ); document.write( "Find b
\n" ); document.write( "b = 3.25*16
\n" ); document.write( "b = 52 yrs is my age
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\n" ); document.write( "lets see if that works out
\n" ); document.write( "\"When you are my age our total equals 140. \"
\n" ); document.write( "52 - 16 = 36 yrs, the difference in our ages
\n" ); document.write( "When your(a) age is 52, I(b) will be: 52 + 36 = 88. 88 + 52 = 140
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