document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=88041>Question 88041</A>: <I><SPAN STYLE=\"word-break: break-all;\"> bill has $3.75 in quarters,dimes,and nickels. he has twice as many quarters as dimes and three more dimes than nickels. find how much of each coin bill has. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #63936 by </B><A HREF=/tutors/aboutme.mpl?userid=rossiv53><B>rossiv53(27)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rossiv53><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=63936\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the number of nickels, x+3 = the number of dimes, and 2(x+3) = the number of quarters.\r<BR>\n" );
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document.write( "So, your equation is <BR>\n" );
document.write( "5x+10(x+3)+25(2(x+3))=375<BR>\n" );
document.write( "5x+10x+30+50x+150=375<BR>\n" );
document.write( "65x+180=375<BR>\n" );
document.write( "65x+180-180=375-180<BR>\n" );
document.write( "65x=195<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "So number of nickels = 3 or .15<BR>\n" );
document.write( "Dimes = 6 or .60<BR>\n" );
document.write( "Quarters = 12 or 3.00\r<BR>\n" );
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document.write( "Value of coins = $3.75  \r<BR>\n" );
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document.write( "Good luck! </SPAN>\n" );
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