document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1023870>Question 1023870</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The base of a right pyramid is a square of a side 24cm and it's height is 16cm<BR>\n" );
document.write( "find the Lateral Area and Volume </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #639359 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=639359\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The base of a right pyramid is a square of a side 24cm and it's height is 16cm<BR>\n" );
document.write( "find the Lateral Area and Volume<BR>\n" );
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document.write( "Each of the 4 faces is a triangle.<BR>\n" );
document.write( "The slant height of the triangle is the hypotenuse of a triangle with legs of 12 & 16 --> 20 cm.<BR>\n" );
document.write( "Area = b*h/2 = 24*20/2 = 240 sq cm.<BR>\n" );
document.write( "LA = 240*4 = 960 sq cm.<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "Vol = base area*height/3 = 576*16/3<BR>\n" );
document.write( "Vol = 3072 cc<BR>\n" );
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document.write( "PS  it's = it is </SPAN>\n" );
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