document.write( "Question 1023777:  A sign says that the price marked on all music equipment is 30%off the original price ,you buy an electric guitar for the sale price of $315 , what was the original price?
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document.write( "How to solve this or what formula should I use \n" );
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| Algebra.Com's Answer #639341 by Theo(13342)     You can put this solution on YOUR website! the basic formulas involved are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sale price = original price minus discount. \n" ); document.write( "discount = original price * discount percent / 100.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let s represent the sale price. \n" ); document.write( "let p represent the original price. \n" ); document.write( "let d represent the discount. \n" ); document.write( "let k represent the discount percent.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the above formulas become:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "s = p - d \n" ); document.write( "d = p * k/100\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "we know that s = 315. \n" ); document.write( "we know that k = 30.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "formulas become:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "315 = p - d \n" ); document.write( "d = p * 30/100\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify these formulas to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "315 = p - d \n" ); document.write( "d = .3p\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since d = .3p, then the first formula can be shown as:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "315 = p - .3p, after we replace d with its equivalent value of .3p.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get 315 = .7p.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "divide both sides of this equation by .7 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "315/.7 = p\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for p to get p = 450.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the original price is 450.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "30% of 450 = 135.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "450 - 135 = 315, which is the sale price.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "numbers look good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solution is that the original price is 450.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it doesn't really matter what variable names you choose as long as you can keep track as to what variable name represents what.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |