document.write( "Question 1023777: A sign says that the price marked on all music equipment is 30%off the original price ,you buy an electric guitar for the sale price of $315 , what was the original price?
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Algebra.Com's Answer #639341 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
the basic formulas involved are:\r
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\n" ); document.write( "\n" ); document.write( "sale price = original price minus discount.
\n" ); document.write( "discount = original price * discount percent / 100.\r
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\n" ); document.write( "\n" ); document.write( "let s represent the sale price.
\n" ); document.write( "let p represent the original price.
\n" ); document.write( "let d represent the discount.
\n" ); document.write( "let k represent the discount percent.\r
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\n" ); document.write( "\n" ); document.write( "the above formulas become:\r
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\n" ); document.write( "\n" ); document.write( "s = p - d
\n" ); document.write( "d = p * k/100\r
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\n" ); document.write( "\n" ); document.write( "we know that s = 315.
\n" ); document.write( "we know that k = 30.\r
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\n" ); document.write( "\n" ); document.write( "formulas become:\r
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\n" ); document.write( "\n" ); document.write( "315 = p - d
\n" ); document.write( "d = p * 30/100\r
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\n" ); document.write( "\n" ); document.write( "simplify these formulas to get:\r
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\n" ); document.write( "\n" ); document.write( "315 = p - d
\n" ); document.write( "d = .3p\r
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\n" ); document.write( "\n" ); document.write( "since d = .3p, then the first formula can be shown as:\r
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\n" ); document.write( "\n" ); document.write( "315 = p - .3p, after we replace d with its equivalent value of .3p.\r
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\n" ); document.write( "\n" ); document.write( "simplify to get 315 = .7p.\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of this equation by .7 to get:\r
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\n" ); document.write( "\n" ); document.write( "315/.7 = p\r
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\n" ); document.write( "\n" ); document.write( "solve for p to get p = 450.\r
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\n" ); document.write( "\n" ); document.write( "the original price is 450.\r
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\n" ); document.write( "\n" ); document.write( "30% of 450 = 135.\r
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\n" ); document.write( "\n" ); document.write( "450 - 135 = 315, which is the sale price.\r
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\n" ); document.write( "\n" ); document.write( "numbers look good.\r
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\n" ); document.write( "\n" ); document.write( "solution is that the original price is 450.\r
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\n" ); document.write( "\n" ); document.write( "it doesn't really matter what variable names you choose as long as you can keep track as to what variable name represents what.\r
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