document.write( "Question 1023806: What is the least positive integer n such that n! is divisible by 1000?\r
\n" );
document.write( "\n" );
document.write( "The sum of the first five terms of an arithmetic sequence is 90 less than the sum of the next five terms. What is the absolute difference between two consecutive terms of this sequence? Express your answer as a common fraction. \n" );
document.write( "
Algebra.Com's Answer #639301 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "1000 = 5*5*5*2*2*2\r\n" ); document.write( "\r\n" ); document.write( "To have a factorial divisible by 1000, it must have 3 factors of 5\r\n" ); document.write( "and 3 factors of 2.\r\n" ); document.write( "\r\n" ); document.write( "Every other integer has a factor of 2 so there are plenty of those,\r\n" ); document.write( "so we must make sure that we have 3 factors of 5 somewhere in the\r\n" ); document.write( "products. Let's start buiding our factorial\r\n" ); document.write( "\r\n" ); document.write( "1*2*3*4*5 <-- that only has 1 factor of 5 \r\n" ); document.write( "(It already has 3 factors of 2)\r\n" ); document.write( "\r\n" ); document.write( "So we keep putting on more factors:\r\n" ); document.write( "\r\n" ); document.write( "1*2*3*4*5*6*7*8*9*10 <-- That only has 2 factors of 5\r\n" ); document.write( "\r\n" ); document.write( "So we keep going once more:\r\n" ); document.write( "\r\n" ); document.write( "1*2*3*4*5*6*7*8*9*10*11*12*13*14*15 <-- that's it!\r\n" ); document.write( "\r\n" ); document.write( "That's 15!. It is the smallest factorial that is divisible by 1000.\r\n" ); document.write( "\r\n" ); document.write( "Notice that 14! = 87178291200 won't do.\r\n" ); document.write( "\r\n" ); document.write( "It only has two 0's on the end, so it's only divisible\r\n" ); document.write( "by 100. But\r\n" ); document.write( "\r\n" ); document.write( "15! = 1307674368000\r\n" ); document.write( "\r\n" ); document.write( "is the smallest factorial that has 3 0's on the end, which\r\n" ); document.write( "a number must have to be divisible by 1000.\r\n" ); document.write( "\r\n" ); document.write( "Answer: 15! = 1307674368000\r\n" ); document.write( "\r\n" ); document.write( "Edwin\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |