document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=88039>Question 88039</A>: <I><SPAN STYLE=\"word-break: break-all;\"> could you help to solve this problem and show in a equation \r<BR>\n" );
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document.write( ". One number is 8 more than another. If the sum of the smaller<BR>\n" );
document.write( "number and twice the larger number is 46, find the two numbers.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #63930 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=63930\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> When you read the problem, it becomes apparent that you need to find a small number and a<BR>\n" );
document.write( "larger number. For ease of understanding and identification, call the Small number S and the<BR>\n" );
document.write( "Larger number L.<BR>\n" );
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document.write( "The first sentence tells you that one number is 8 more than another. If it is 8 more, then<BR>\n" );
document.write( "this means that it is L. So you should get the idea that if you take 8 away from L  then you<BR>\n" );
document.write( "should have S. You can write this as:<BR>\n" );
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document.write( "L - 8 = S<BR>\n" );
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document.write( "or by adding 8 to both sides, it may be clearer to you as S + 8 = L.  Either one is OK to use.<BR>\n" );
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document.write( "The second sentence tells you that the sum of the Small number (S) and twice the Larger number<BR>\n" );
document.write( "(2*L) equals 46. Writing this in equation form gives you:<BR>\n" );
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document.write( "S + 2L = 46   <- call this the second equation<BR>\n" );
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document.write( "Then, from the first equations you can either use the fact that S = L - 8 or that L = S + 8<BR>\n" );
document.write( "and substitute into the second equation. For ease, let's use S = L - 8 and so we can replace<BR>\n" );
document.write( "S in the second equation with L - 8 to get:<BR>\n" );
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document.write( "L - 8 + 2L = 46<BR>\n" );
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document.write( "Next you can get rid of the -8 on the left side by adding 8 to both sides.  When you do<BR>\n" );
document.write( "this addition you get:<BR>\n" );
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document.write( "L + 2L = 54<BR>\n" );
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document.write( "Add the terms on the left side and the equation reduces to:<BR>\n" );
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document.write( "3L = 54<BR>\n" );
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document.write( "Finally divide both sides by 3 to reduce the equation and solve for L:<BR>\n" );
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document.write( "L = 54/3 = 18<BR>\n" );
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document.write( "Now you know that L = 18 you can solve for S. You know that L is 8 larger than the smaller<BR>\n" );
document.write( "number S. So you can subtract 8 from L and you have S. Therefore, L - 8 = 18 - 8  = 10. Therefore,<BR>\n" );
document.write( "S is 10.<BR>\n" );
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document.write( "So the two numbers are 10 and 18.<BR>\n" );
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document.write( "Obviously the larger number is 8 more than the smaller number. Then check further by<BR>\n" );
document.write( "adding the smaller number to twice the larger. If you do you get 10 + 2*18 and this becomes<BR>\n" );
document.write( "10 + 36 and this equals 46, just as the problem says it should.<BR>\n" );
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document.write( "Hope this helps you to understand the problem and how to solve it.<BR>\n" );
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