document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1023733>Question 1023733</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 24 is added to a certain number and the sum is divided by 6, the result is 1 more than 13 of the original number. Find the original number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #639248 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=639248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the number, x.  Then we have<BR>\n" );
document.write( "(24+x)/6 = 1 + 13x<BR>\n" );
document.write( "Multiply by 6 and get<BR>\n" );
document.write( "24 + x = 6 + 78x<BR>\n" );
document.write( "18 = 77x<BR>\n" );
document.write( "x = 18/77<BR>\n" );
document.write( "I think you probably wrote the question wrong, but that is the answer for the question as written. </SPAN>\n" );
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